436=t^2-55t

Solution for 436=t^2-55t equation:

436=t^2-55t

We move all terms to the left:

436-(t^2-55t)=0

We get rid of parentheses

-t^2+55t+436=0

We add all the numbers together, and all the variables

-1t^2+55t+436=0

a = -1; b = 55; c = +436;
Δ = b2-4ac
Δ = 552-4·(-1)·436
Δ = 4769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-\sqrt{4769}}{2*-1}=\frac{-55-\sqrt{4769}}{-2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+\sqrt{4769}}{2*-1}=\frac{-55+\sqrt{4769}}{-2}
$